Friday Sep. 9, 2011
click here to download today's notes in a more printer friendly format

Music from Rodrigo y Gabriela before class this afternoon.  You heard "Hanuman", "Diablo Rojo", and "Vikingman."  They also do a nice version of "Stairway to Heaven."

The Practice Quizzes have been graded and were returned in class today.  The average was 65% which is low, but as you can see below, pretty typical.

Semester
MWF
class
T Th
class
F11
65%
???
S11
62%
---
F10
60%
67%
S10
62%
61%
F09
66%
68%
S09
60%
---
F08
64%
65%
S08
64%
66%

If you didn't take the Practice Quiz you should at least print out a copy to study for Quiz #1 on Sept. 21.  The answers are online.

The Optional Assignment turned in last Friday was also returned.  Not having a grade marked on your paper means you earned full credit (0.3 extra credit pts).


Today
You'll get a chance to lift the 14.7 pound steel bar.  It's surprising heavy.  An air pressure of 14.7 psi (at sea level) is a sizable force.  And as we'll learn during the class today air (at sea level) is also pushing upward and sideways with the same amount of force.

You'll be able to feel how heavy and dense mercury is.  That's one reason it is used in barometers to measure air pressure.

I brought 5 bricks to class today to help explain why pressure decreases with increasing altitude.  I carried them to school yesterday in my back pack.  I've been carrying a lot of heavy stuff around this week and am starting to feel like of of  Los Penitentes.  I'm originally from New Mexico and remember hearing stories about them when I was younger.

Decreasing pressure with increasing altitude is what causes hot air balloons to rise (gravity causes them to sink).

We'll look at how and why air density changes with altitude.

And near the end of class I have a short "upward pressure force" demonstration.



You can learn a lot about pressure from bricks. 

For example the photo below (taken in my messy office) shows two of the bricks from class.  One is sitting flat, the other is sitting on its end. 
Each brick weighs about 5 pounds.  Would the pressure at the base of each brick be the same in this kind of situation? 



Pressure is determined by (depends on) weight so you might think the pressures would be equal.  But pressure is weight divided by area.  In this case the weights are the same but the areas are different.  In the situation at left the 5 pounds must be divided by an area of about 4 inches by 8 inches = 32 inches.  That works out to be about 0.15 psi.  In the other case the 5 pounds should be divided by a smaller area, 4 inches by 2 inches = 8 inches.  That's a pressure of 0.6 psi, 4 times higher.  Notice also these pressures are much less the 14.7 psi sea level atmospheric pressure.

The main reason I brought the bricks was so that you could understand what happens to pressure with increasing altitude.  Here's a drawing of the 5 bricks stacked on top of each other.


At the bottom of the pile you would measure a weight of 25 pounds (if you wanted to find the pressure you'd divide 25 lbs by the 32 square inch area on the bottom of the brick).  If you moved up a brick you would measure a weight of 20 pounds, the weight of the four bricks that are still above.  The pressure would be less.  Weight and pressure will decrease as you move up the pile.

The atmosphere is really no different.  Pressure at any level is determined by the weight of the air still overhead.  Pressure decreases with increasing altitude because there is less and less air remaining overhead.  The figure below is a more carefully drawn version of what was done in class.



At sea level altitude, at Point 1, the pressure is normally about 1000 mb.  That is determined by the weight of all (100%) of the air in the atmosphere.

Some parts of Tucson, at Point 2, are 3000 feet above sea level (most of central Tucson is a little lower than that around 2500 feet).  At 3000 ft. about 10% of the air is below, 90% is still overhead.  It is the weight of the 90% that is still above that determines the atmospheric pressure in Tucson.  If 100% of the atmosphere produces a pressure of 1000 mb, then 90% will produce a pressure of 900 mb. 

Pressure is typically about 700 mb at the summit of Mt. Lemmon (9000 ft. altitude at Point 3) and 70% of the atmosphere is overhead..

Pressure decreases rapidly with increasing altitude.  We will find that pressure changes more slowly if you move horizontally.  Pressure changes about 1 mb for every 10 meters of elevation change.  Pressure changes much more slowly normally if you move horizontally: about 1 mb in 100 km.  Still the small horizontal changes are what cause the wind to blow and what cause storms to form.

Point 4 shows a submarine at a depth of about 30 ft. or so.  The pressure there is determined by the weight of the air and the weight of the water overhead.  Water is much denser and much heavier than air.  At 30 ft., the pressure is already twice what it would be at the surface of the ocean (2000 mb instead of 1000 mb).


What difference does it make if pressure decreases with increasing altitude?
Here's one answer to that question.


Hot air balloons can go up and come back down.  I'm pretty sure you know what would cause the balloon to sink.  I suspect you don't know what causes it to float upward.




Gravity pulls downward on the balloon.  The strength of this force will depend on whether the air is hot low density air (light weight) or cold higher density air (heavier air).

Pressure from the air surrounding the balloon is pushing against the top, bottom, and sides of the balloon (the blue arrows shown above at right).  Pressure decreases with increasing altitude.  The pressure at the bottom pushing up is a little higher than at the top pushing down (the pressures at the sides cancel each other out).  Decreasing pressure with increasing altitude creates an upward pointing pressure difference force that opposes gravity.


What about density.  How does air density change with increasing altitude?  You get out of breathe more easily at high altitude than at sea level.  Air gets thinner (less dense) at higher altitude. 

Because air is compressible, a stack of mattresses might be a more realistic representation of layers of air than a pile of bricks.

Four mattresses are stacked on top of each other.  Mattresses are reasonably heavy, the mattress at the bottom of the pile is compressed by the weight of the three mattresses above.  This is shown at right.  The mattresses higher up aren't squished as much because their is less weight remaining above.  The same is true with layers of air in the atmosphere.


The statement above is at the top of p. 34 in the photocopied ClassNotes.  I've redrawn the figure found at the bottom of p. 34 below.

There's a lot of information in this figure and it is worth spending a minute or two looking at it and thinking about it.

1. You can first notice and remember that pressure decreases with increasing altitude.  1000 mb at the bottom decreases to 700 mb at the top of the picture.

2a.  Each layer of air contain the same amount (mass) of air.  This is a fairly subtle point.  You can tell because the pressure drops by 100 mb as you move upward through each layer.   Pressure depends on weight.  So if all the pressure changes are equal, the weights of each of the layers must be the same.  Each of the layers must contain the same amount (mass) of air (each layer contains 10% of the air in the atmosphere). 

2. The densest air is found in the bottom layer.  The bottom layer is compressed the most because it is supporting the weight of all of the rest of the atmosphere.  It is the thinnest layer in the picture and the layer with the smallest volume.  Since each layer has the same amount of air (same mass) and the bottom layer has the smallest volume it must have the highest density.  The top layer has the same amount of air but about twice the volume.  It therefore has a lower density (half the density of the air at sea level).

3.  Finally something I'll just point out. 
The rate of pressure change with altitude depends on air density.  Pressure is decreasing most rapidly with increasing altitude in the densest air at the bottom of the picture.


Pressure at any level in the atmosphere depends on (is determined by) the weight of the air overhead.  We used a pile of bricks (each brick represents a layer of air) to help visualize and understand why pressure decreases with increasing altitude.  A pile of bricks can lead to the believe that air pressure exerts force in just a downward direction. 


Air pressure is a force that pushes downward, upward, and sideways.  If you fill a balloon with air and then push downward on it, you can feel the air in the balloon pushing back (pushing upward).  You'd see the air in the balloon pushing sideways as well.

The air pressure in the four tires on your automobile pushes pushes upward with enough force to keep the 1000 or 2000 pound vehicle off the road.  The air pressure also pushes downward, you'd feel it if the car ran over your foot.

Another helpful representation of air in the atmosphere might be a people pyramid.



If the bottom person in the stack above were standing on a scale, the scale would measure the total weight of all the people in the pile.  That's analogous to sea level pressure being determined by the weight of the all the air above.

The bottom person in the picture above must be strong enough to support the weight of all the people above.  That is equivalent to the bottom layer of the atmosphere pushing upward with enough pressure to support the weight of the air above.


This was a logical point to do a demonstration.  A demo that tries to prove that air pressure really does push upward as well as downward.  Not only that but that the upward force is fairly strong.  The demonstration is summarized on p. 35 a in the ClassNotes.


Don't worry too much about the details above because there's a more detailed explanation is below.  At this point you should wonder why is it that the water in a balloon will fall while the water in the wine glass does not.


Here's a little bit more detailed and more complete explanation of what is going on.  First the case of a water balloon.



The figure at left shows air pressure (red arrows) pushing on all the sides of the balloon.  Because pressure decreases with increasing altitude, the pressure from the air at the top of the balloon pushing downward (strength=14) is a little weaker than the pressure from the air at the bottom of the balloon that is pushing upward (strength=15).  The two sideways forces cancel each other out.  The total effect of the pressure is a weak upward pressure difference force (1 unit of upward force shown at the top of the right figure). 

Gravity exerts a downward force on the water balloon.  In the figure at right you can see that the gravity force (strength=10) is stronger than the upward pressure difference force (strength=1).  The balloon falls as a result.  This is what you know would happen if you let go of a water balloon, it would fall.


In the demonstration a wine glass is filled with water.  A small plastic lid is used to cover the wine glass.  The wine glass is then turned upside and the water does not fall out.




All the same forces are shown again in the left most figure.  In the right two figures we separate this into two parts.  First the water inside the glass isn't feeling the downward and sideways pressure forces (because they're pushing on the glass, they're included on the right figure ).  Gravity still pulls downward on the water but the upward pressure force is able to overcome the downward pull of gravity.  It can do this because all 15 units are used to overcome gravity and not to cancel out the downward pointing pressure force.  The net upward force is strong enough to keep the water in the glass.

The demonstration was repeated using a 4 Liter flash (more than a gallon of water, more than 8 pounds of water).  The upward pressure force was still able to keep the water in the flask (much of the weight of the water is pushing against the sides of the flask which the instructor was supporting with his arms).