Tuesday Feb. 10, 2009

The first set of homework problems has been graded and was returned in class together with a set of solutions (not that you really needed them).


Be sure you get the E field polarities right in the dE/dz calculation.


When you are figuring out the E field at values of r < R, only a portion of the space charge is inside the Gaussian surface.  For values r > R, all of the space charge is inside the volume.  Your two expressions for E(r) should be the same at r = R.

There will always be an attractive force between a charge and a conducting plane.  The charge will cause charges of the opposition polarity to be induced on the surface of the conductor.

Be sure to multiply the surface charge density by an increment of area when determining the total amount of charge induced on the conduction plane.

These next few pages show some actual measurements of current density, E field, and conductivity (fair weather values). 


There was pretty good agreement among measurements made with different sensors.

The authors mentioned that the measured values of Jz were almost exactly half of what one would obtain by multiplying the total conductivity by the electric field.  The explanation for this is shown below:

One of the Jz sensors consisted of two conducting hemispheres insulated from each other.  Charge is induced on the two hemispheres by the ambient electric field.  The figure above shows that the sensor is only capturing half of the charge carries in the atmosphere and therefore only measuring half of the current density, Jz.

Some additional measurements from "the yellow book."  Note how uniform Jz is with altitude.


Next we will look at ionizing radiation (from the ground, gases in the ground that escape into the air, and cosmic rays).  Ionized air molecules become "small ions."  The small ions are what gives the air its conductivity.


Radioactive materials in the ground emit alpha and beta particles, and gamma rays.  Alpha particles (helium nucleus: two protons and two neutrons) are a strong source of ionization but only in the first few cm above the ground.  Beta particles (electrons) ionize air in a layer a few meters thick.  The effects of gamma radiation extend of 100s of meters.  Radon gas is discussed in more detail below.  Cosmic rays are the dominant source of ionization over the ocean and above 1 km over land.

A short handout with some information about radon was distributed in class.  You can download a copy of the handout here.

The following figure shows a portion of the decay series that ultimately yield isotopes of radon.

Because of its relatively short half like, all the Neptunium in the ground has decayed.  Two isotopes of radon have half lives long enough to be able to diffuse out of the soil and into the air.  The three isotopes of radon are sometimes referred to al radon, actinon, and thoron.  All three isotopes are also known as emanatium.

The following calculation is an example of how you might go about calculating the ion pair (ip) production rate.



We first determine the number of alpha particles emitted in a cubic centimeter of air per second.
Next we determine how many air molecules an alpha particle can ionize.

Multiplying the alpha particle emission rate by the number of ionized air molecules per alpha particle gives the ion pair production rate.

This next figure gives some typical ip production rates from the various radiation sources as a function of altitude.


Finally a little information about cosmic rays

And some historical information



Here is some information on cosmic ray showers.  Very few of the primary particles reach the ground.  Rather they interact with gas molecules in the atmosphere and produce a wide variety of types of secondary particles.