Your homework must be typed. Make sure you read and answer all the parts to
each question!
1.
“Advection fog”
is common along the northern
(a)
Explain why fog
forms when the warm, moist air contacts the much colder coastal waters.
(b)
Over land, this
fog often persists through the morning hours, but “burns off” as the afternoon
wears on. This occurs because some
sunlight is able to penetrate through the fog and warm the ground. Explain how this would act to dissipate the
fog (of course, the fog doesn’t actually “burn”). Would you expect the fog to dissipate from
the bottom up or from the top down?
Explain.
2. The
rain shadow effect. As air is forced to
rise up a mountain, clouds may form.
Some of the condensed water may then rain out of the clouds on the
windward slopes and mountain tops. After
the air moves over the mountain top, it is forced to sink back down on the
leeward side of the mountain. In this
sinking air, any remaining clouds will evaporate as the air warms by
compression. At the bottom of the
leeward side of the mountain, the air is often warmer and much less humid than
it was before it was forced up and over the mountain. Answer the following questions and fill in
tables for each part below. Create your
own tables (using WORD perhaps). You are
going to follow a parcel of air that is forced to rise up a mountain, then sink
back down the other side of the mountain.
(a) Fill in the table below for an air parcel forced to rise from 0 meters
up to the top of a 6,000 m mountain. At what altitude will a cloud start to
form?
Altitude |
Parcel Temperature |
Parcel Dew point Temperature |
6,000 m |
|
|
5,000 m |
|
|
4,000 m |
|
|
3,000 m |
|
|
2,000 m |
|
|
1,000 m |
|
|
0m |
20º C |
10º C |
(b) Bring the parcel back down
the other side of the mountain. Initially
the parcel contained 7 g of water vapor per kilogram of dry air. This is based on a dew point temperature of
10° C and the table of saturation mixing ratios that was distributed as a class
handout. Assume that 59% of the total
amount of water in the parcel fell out of the parcel as rain or snow on the
mountain. This means that the parcel
contains only 3 g of water per kilogram of dry air just before it is forced to
come down the other side of the mountain. Fill in
the table below for the air parcel being forced to sink from 6,000 m down to 0
m. (HINTS: when parcels move down in
the atmosphere, they warm by compression.
Unsaturated parcels warm by 10º C for every 1000 m drop in
elevation. Parcels that contain clouds
warm more slowly because energy is required to evaporate the cloud, therefore a
parcel which contains a cloud warms by only 6º C for every 1000 m drop in
elevation until the entire cloud evaporates.
Keep in mind that as a cloud evaporates, the dew point temperature will
change. You will have to determine when
the cloud completely evaporates from the parcel. This happens when all of the water is in the
form of water vapor. For a mixing ratio
of 3 g of water vapor per kilogram of dry air, the air is saturated at a
temperature of -2° C. This means that
the dew point temperature of the sinking parcel can not become higher than -2°
C.
Altitude |
Parcel Temperature |
Parcel Dew point
Temperature |
6,000 m |
* (from part a) |
* (from part a) |
5,000 m |
|
|
4,000 m |
|
|
3,000 m |
|
|
2,000 m |
|
|
1,000 m |
|
|
0 m |
|
|
* to get started you need to
copy the values you computed at 6000 m from the table in Part (a)
(c) Explain why the parcel in part (b) arrives back on the ground warmer
than it was before it went up and over the mountain.
3.
Answer the
following questions or fill in tables for each part below. Create your own tables (using WORD perhaps).
The lifted index (This is
labeled as LI in the equations below) is defined as the difference between the
environmental air temperature at 500 mb (This is labeled as T500 in
the equation below) and the air temperature inside an air parcel after it has
been lifted from the surface up to 500 mb (This is labeled as TParcel
in the equation below). Meteorologists use the lifted index to access the
stability of the atmosphere.
LI = T500 - TParcel
(a) Explain why
the atmosphere is said to be stable when the lifted index is positive and
unstable when the lifted index is negative.
(b) The following
information is available for
Air Pressure |
Altitude (m) |
Atmospheric Temperature (°C) |
Parcel Temperature (°C) |
Parcel Dew Point (°C) |
500 mb |
5500 |
-20 (this is T500) |
(the value you fill in this box will be TParcel) |
|
---------- |
4500 |
-13 |
|
|
---------- |
3500 |
-6 |
|
|
---------- |
2500 |
1 |
|
|
---------- |
1500 |
8 |
|
|
---------- |
500 |
10 |
10 |
0 |
(c)
Later that day at
3:00 PM, the following conditions were measured in
Air Pressure |
Altitude (m) |
Atmospheric Temperature (°C) |
Parcel Temperature (°C) |
Parcel Dew Point (°C) |
500 mb |
5500 |
-20 |
|
|
---------- |
4500 |
-13 |
|
|
---------- |
3500 |
-5 |
|
|
---------- |
2500 |
3 |
|
|
---------- |
1500 |
11 |
|
|
---------- |
500 |
20 |
20 |
0 |
(d) What change took place in
the atmosphere between 8:00 AM and 3:00 PM that caused the stability of the
atmosphere to change? Explain why this
change tends to make the atmosphere more unstable.
End of homework.
There will not be a 4th question.